Midterm 2 Study Guide
- Provide definitions for the terms and statements for the theorems:
- A number being prime
- A number being composite
- Fundamental Theorem of Arithmetic
- State in mathematical terms and either prove or provide a counterexample:
- If two numbers are equal modulo \(n\) when multiplied by a third number, then the numbers are equal modulo \(n\).
- Every natural number is either prime or composite (but not both)
- Every natural number greater than 1 is divisible by some prime number.
- A number is prime if and only if all primes not exceeding its square root don’t divide it.
- Two distinct primes are relatively prime.
- If a prime number divides a product, then it must divide one of the factors.
- A power of a number divides the same power of another number if and only if the first number divides the second.
- There are natural numbers that solve the equation \(6n^2=m^2\).
- If two numbers divide a third, then their product also divides it.
- If two relatively prime numbers divide a third, then their product also divides it.
- If two numbers have the property that whenever they divide a third number then their product also divides it, then the numbers must be relatively prime.
- A prime number either divides another number or is relatively prime to it.
- If a number is relatively prime to two other numbers, then it is also relatively prime to their product.
- Any two consecutive integers are relatively prime.
- If two numbers are relatively prime, any divisors of them are also relatively prime.
- If two numbers are relatively prime, any multiples of them are also relatively prime.
- For every integer there is a prime larger than it.
- Prove:
- The equation \(ax+by=c\) has a solution in integer \(x,y\) if and only if \(\gcd(a,b)\) divides \(c\).
- If \(a x_0 + b y_0 = c\), then all the solutions to the equation \(ax+by=c\) are given by the formulas \(x=x_0+k\frac{b}{\gcd(a,b)}\), \(y=y_0 - k\frac{a}{\gcd{a,b}}\). (Two questions here: that all these pairs are solutions,for every \(k\), and that any solution has this form).
- If \(p\) and \(q_1, \ldots, q_n\) are primes and \(p|q_1\cdots q_n\), then there is an \(i\) such that \(p=q_i\).
- If \(n>1\) is a number with the property that whenever \(n|ab\) it follows that \(n|a\) or \(n|b\), then \(n\) must be prime.
- If \(\gcd(b,c)=1\) then \(\gcd(a,bc)=\gcd(a,b)\gcd(a,c)\).
- If \(a'=\frac{a}{\gcd(a,b)}\) and \(b'=\frac{b}{\gcd(a,b)}\), then \(\gcd(a',b')=1\).